Section 3 Answers 7 3 Answers 1 y = Ax, 2 y2x−x2 = A, 3 (y 1)ex −y2 = A, 4 x2y 3x2 y4 = A, 5 1 2 x 2(1−y )4y2 = A, 6 1 4 e 4x x2y2 siny = A, 7 x3 ysinx−y4 = A, 8 x2 2 tan −1 y = A, 9 x2 x3y3 3 y 4 = A, Toc JJ II J I BackSimplify 3x^2(2xy3xy^24x^2y^3) Apply the distributive property Simplify Tap for more steps Multiply by by adding the exponents Tap for more steps Move Multiply by Tap for more steps Raise to the power of Use the power rule to combine exponents Add andMay I use the fact that the function $$\begin{array}{ll} f(x, y) = 2xy 3x\\ \text{subject to} & x 2y = \end{array}$$ is negative coercive in that $\lim_{x\to
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3x+2y=2xy 1/x+2/y=7/6
3x+2y=2xy 1/x+2/y=7/6-2xy9x^2 (2yx^21) (dy)/ (dx)=0, y (0)=3 \square!= x – 2y 3z – 3x – 5y 7 Collecting positive and negative like terms together, we get x – 3x – 2y 5y 3z 7 = –2x – 7y 3z 7 Question How much is x 2 − 2xy 3y 2 less than 2x 2 − 3y 2 xy?



Solution
Well, see 3x^2 xy 2y^2 The coefficients of x^2 and y^2 are 3 and 2 Their product is 6 See the coefficient of xy, it is 1 Next find theBài 1 (1,5 điểm) Phân tích các đa thức sau thành nhân tử a) 3xy^3 7xy^2 − 6xy b) (3x^2 4xy y^2) − 2x − 2y Bài 2 (1,5 điểm) Tìm x, biết a) 4 (x 3)2 − (2x 7) (2x − 4) = 0 b) x^3 8 − 4 (x^2 − 4) = 0 Bài 3 (2 điểm) Cho biểu thức A= (63x/2x 4x^2/x^240 y 2 Solution We look for the critical points in the interior
Factor 3x^22xyy^2 Factor by grouping Tap for more steps For a polynomial of the form , rewrite the middle term as a sum of two terms whose product is and whose sum is Tap for more steps Reorder terms Reorder and Factor out of Rewrite as plus Apply the distributive propertyExample 5712 Find and classify all critical values for the following function f(x,y)=x3 12xy 8y3 First, we need to find the zeros of the partial derivatives Those partials are • fx(x,y)=3x2 12y • fy(x,y)=12x24y2 Set both of these partial derivatives to zero • y =(1/4)x2 • x = 2y2 Next, we solve the system of equations y =(1/4 Lời giải \(3x^2y^2z^22x2y2xy3=0\) \(\Leftrightarrow (x^2y^212xy2y2x)2(x^22x1)z^2=0\) \(\Leftrightarrow (xy1)^22(x1)^2z^2=0\)
Answer (1 of 2) I think that the equation is this one y^2 x^2y' = xyy' Take y =xV(x) ,then dy/dx = V xdV/dx The equation becomes (x^2)( xV' V) x^2V^2 (x^2)(xV' V)V=0 Dividing by x^2 obtain x(1V)dV/dx V =0 This can be separated as (V 1)dV/V = dx/x Integrating gives VDerivative of 2xy \square! DIFFERENTIAL EQUATIONS FIRST ORDER DIFFERENTIAL EQUATIONS Solve differential equation 2xy9x^2 (2yx^21)dy/dx=0, y (0)= 3 Chesley Answered Solve differential equation 2xy − 9x2 (2y x2 1)dy / dx = 0, y (0)= 3 Your answer Email me at this address if my answer is selected or commented on Email me if my answer is



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Bentuk sederhana dari 5 x 2 y − 3 x y 2 − 7 x 2 y 6 x y 2 5x^2y\ 3xy^{2\ }7x^2y6xy^2\ \ \ \ 5 x 2 y − 3 x y 2 − 7 x 2 y 6 x y 2 adalah answer choices 3 x y 2 − 12 x 2 y 3xy^212x^2y 3 x y 2 − 1 $\begingroup$ Thank you for you explanation, but suppose that I wanted to use the Lagrange system to compute the critical points How could I show that the critical point found is a actually a max?Move all terms containing x to the left, all other terms to the right Add '6y' to each side of the equation 5x 6y 6y = 0 6y Combine like terms 6y 6y = 0 5x 0 = 0 6y 5x = 0 6y Remove the zero 5x = 6y Divide each side by '5' x = 12y Simplifying x = 12y




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10INTEGRATING FACTORS 37 02 EquationswithIntegratingFactorsthatdependonlyonyConsideragainthegeneral firstorderdifferentialequation (1014) M(x,y)N(x,y)Easy as pi (e) Unlock StepbyStep plot 3x^22xyy^2=1 Natural Language Math Input NEW Use textbook math notation to enter your math Try itAnswer (1 of 2) Solve three simultaneous equ'ns z2y = 13x ===> 3x 2y z = 1 (1) 2x3y = 4z5 ==> 2x 3y 4z = 5 (2) 4x = 2xy6–3z ==> 2x y



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How do i go from 3x^2 xy 2y^2 to (xy)(3x2y)?Solution Question 22 What mustAnswer (1 of 6) Solve \left(3x^22xy3y^2\right) \, \mathrm{d}x = 4xy \;



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2 (Sec 26 Problem 4) (2xy 22y)(2x y 2x)y0 = 0 Solution Let M(x,y) = 2xy2 2y and N(x,y) = 2x2y 2x We have M y = 4xy 2 and N x = 4xy 2 So M y = N x and the given equation is exact Thus there is a function φ(x,y) such that φ x = M = 2xy2 2y andR φ y = N = 2x2y2x Integrating the first equation, we have φ(x,y) = (2xy2 2y Show that following differential equation is not exact (3x^2y^4 2xy)dx (2x^3y^3 x^2)dy = 0 Then find an integrating factor to solve the differential equation Question Show that following differential equation is not exact (3x 2 y 4 2xy)dx (2x 3 y 3 x 2)dy = 0 Then find an integrating factor to solve the differential equation The solution of the differential equation (3xy y^2)dx (x^2 xy)dy = 0 is (A) x^2(2xy y^2) = c^2 asked in Differential equations by AmanYadav ( 557k points) differential equations




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\mathrm{d}y \tag*{} Divide both sides by x^2 \left(3\frac{2y}{x}\frac{3y^2}{x^2}\right 3xy2 dy dx 2x2y dy dx y3 2xy2 = 0 Factor and move terms without a dy dx factor to right side dy dx (3xy2 2x2y) = − y3 −2xy2 now divide both sides by 3xy2 2x2y and factor where you can dy dx = −y2(y 2x) yx(3y 2x) dy dx = −y(y 2x) x(3y 3x) Now evaluate at the given point (2,1) dy dx = −1(1 2(2)) 2(3(1) 2(2)) = −1 Integrating leads to y=v^22, which is y=(x^2/y^2)2 but in my book the answer comes with an additional factor of two in the answer so the right answer should be y=(x^2/2y^2)2




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Solution for 3x^22xyy^2=0 equation Simplifying 3x 2 2xy 1y 2 = 0 Reorder the terms 2xy 3x 2 1y 2 = 0 Solving 2xy 3x 2 1y 2 = 0 Solving for variable 'x' Factor a trinomial (x 1y)(3x y) = 0 Subproblem 1 Set the factor '(x 1y)' equal to zero and attempt to solve Simplifying x 1y = 0 Solving x 1y = 0 Move all terms containing x to the left, all other terms Solving A System Of Equations Using A Matrix Precalculus Socratic Find The Value Of X And Y If 2x 3y 2 3 4 0 And 3x 2y 2 2 1 5 Simplify Do not use negative exponents in the answer 12x2y4 3xy7 There should be a line between like a fraction but it did not copy or paste This is the answer I got 12 x^2 y^4 = 12y^4/x^2 3xy^7 = 3x/y^7 it was wrongAnswer The monomials, binomials, trinomials and quadrinomials are as follows (i) a 2 is a monomial expression as it contains one term only (ii) a 2 b 2 is a binomial expression as it contains two terms (iii) x 3 y 3 z 3 is a trinomial expression as it contains three terms (iv) x 3 y 3 z 3 xyz is a quadrinomial expression as it contains four terms (v) 7 5 = 12 is a monomial



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1 2 p x y 2x 2y = 2xy 1 2 p x y To simplify a little we multiply both sides through by 2 p x y dy dx 1 4x2y p x y = 4xy2 x y 1 dy dx = (4xy2 p x y) 1 1 4x2y p x y 7Find all the xcoordinates of the points on the curve x2y2 xy= 2 where the slope of the tangent line is 1 We need to nd the derivative dy dx by implicit di erentiationProblem 2 Determine the global max and min of the function f(x;y) = x2 2x2y2 2y2xy over the compact region 1 x 1;Solution Question 21 How much does a 2 − 3ab 2b 2 exceed 2a 2 − 7ab 9b 2?



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SOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sidesClick here👆to get an answer to your question ️ Simplify (3x 2y)^2 (3x 2y)^21 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 15 6 1 1 7 21 35 35 21 7 1 Combinations Combinations will be discussed more fully in section 76, but here is a brief summary to get you going with the Binomial Expansion Theorem



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Solve the differential equation (x^2 y^2)dy/dx = 2xy given that y = 1, x = 1 asked in Differential equations by AmanYadav ( 557k points) differential equations At what point on the curve x = 3t2 7,y = t3 − 8 does the tangent line have slope 1/2 AP AB Calculus Linear approximation Consider the curve defined by 8x^2 5xy y^3 = 149 a find dy/dx b write an equation for the tangent line to the curve at the point (4,1) cImplicit differentiation is a way of differentiating when you have a function in terms of both x and y For example x2 y2 = 16 This is the formula for a circle with a centre at (0,0) and a radius of 4 So using normal differentiation rules x2 and 16 are differentiable if we are



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Get stepbystep solutions from expert tutors as fast as 1530 minutesGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us! Solve $(3x^2y^4 2xy)dx (2x^3y^3 x^2)dy$ This is not one of the standard forms and neither is it an exact form How do I go about doing this



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Do the grouping x^{2}2xy3x6y=\left(x^{2}2xy\right)\left(3x6y\right), and factor out x in the first and 3 in the second group \left(x2y\right)\left(x3\right) Factor out common term x2y by using distributive property Examples Quadratic equation { x } ^ { 2 } 4 x 5 = 0 Trigonometry 4 \sin \theta \cos \theta = 2 \sin \thetaArea of a circle?Yes (4) No (1) Deepak Sharma 8 years AGO (6x^2xy) (2xyy^2)=61 6x^2xy=6 (2xyy^2) 6x^213xy6y^2=0 (2x3y) (3x2y)=0if we take 2x3y=0then xy=32 & if we take 3x2y=0 then xy=23 so option 8 is correct



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EXAMPLE root(3,x^7)=root(3,x^6*x)=root(3,x^6)root(3,x)=x^2root(3,x) The cases when there are fractions in the radicand and radicals in the denominator of a fraction will be discussed later EXAMPLE Put root(2^3x^5) in standard form1 y' y = 2, y (0) = 0 2 y' 2y = 3e^2x, y (0) = 0 3 y' = 3y = 2xe^3x 4 y' 2xy = e^x^2 5 xy' 2y = 3x, y (1) = 5 6 xy' 5y = 7x^2, Question Find general solutions of the differential equations in Problems 1 through 25 If an initial condition is given, find the corresponding particular solutionTranscribed image text 4 y' 2x 5 xy, 2y =3x, y(1) = 5 6 xy' 5y = 7x2, y (2) = 5 7, 2xy' y = 10VF 8 3xy y 9 xy,y = x, y(1) = 7 10 2xy'3) 11 xy' y



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X^2 2 y^2 = 1 Natural Language;Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music Factorize x 2 2xy y 2 – 9 Factorize x 2 2xy y 2 – 9 In mathematics, It is an expression that is made up of variables and constants along with algebraic operations such as addition, subtraction, etc these Expressions are made up of terms Algebraic expressions are the equations when the operations such as addition, subtraction



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16) p q r =1 p2q3r=4 4p5q6r=7 18) x 2y − 3z =9 2x − y2z = − 8 3x − y − 4z =3 ) 4x − 7y3z =1 3x y − 2z =4 4x − 7y3z =6 22) 3x y − z = 10 8x − y − 6z = − 3 5x − 2y − 5z =1 6Y = 2xy bx2 = 3x2 2xy = N x So b = 3 With this, find the solution to the DE f(x,y) = Z M dx = Z xy 23x2ydx = 1 2 x y2 x3y g(y) And solve for g(y) f y = x 2y x3 g0(y) = x3 x y So we didn't need g(y) This leaves 1 2 x 2y x3y = C 6 Problem 18 Done in Class The idea is M(x)N(y) dy dx = 0 Given that, M y = 0 and N x = 0, so the1) xy=5 3xy=7 2) 2xy=32x5y=9 3) 3x5y=0 2x5y=25 4) 4xy=6 4x3y=18 5) 2xy=52x5y=11 6) 8=4x3y 17=x3y 7) 6=3xy 10=5xy 8) 3x8y=13xy=17 9) x2y=15 5x=2y3 10) 7xy=123y=7x8 11) y=3x13 2x=y9 12) 4x12=7yy12=4x 13) 3x2y=6 y=x3 14) x4y=4 y=x1 15) 300x125y=1350 y2=8 16) 2xy=6 1/6x1/12y=1/2 17)4x4y=5 x4y=5/2




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MA 351 Fall 07 Exam #3 Review Solutions 4 6 Evaluate ZZ D x p y2 x2dA, D= f(x;y)j0 y 1;0 x yg ZZ D x p y2 x2dA= Z 1 0 Z y 0 x(y2 x2)12 dxdy (use usub on y2 x2) Z 1 0 1 3 (y2 x2)3=2 x=y x=0 dy= Z 1 0 1 3 (y2 y2)3=2 1 3 (y2)3=2 dy Z 1 0 1 12 y3 dy= 1 12 y4 1 0 = 1 12 7 Find the volume of the solid under the paraboloid z= x 2 y 4 and the planes x= 0, y= 0, z= 0 and x y= 1



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